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Let's continue after lecture 3 Jet strikes at the centre of stationary symmetric curved plate Let us consider a stationary flat plate on the centre of which water Jet striking perpendicularly, denote this centre point of plate as point 1, which is entry point of water jet. After striking the plate water will split equally in two parts. Let's consider waterjet is coming out of nozzle with mass flow rate 'm' and with velocity 'V1'. After splitting into equal parts, water will exit from top and bottom ends of the plate. Denote both of these end points of plate with point 2, which is exit point of water jet. The mass flow rate exiting from top end of plate is 'm/2' and with exit velocity V2. Similarly the mass flow rate exiting from bottom end of plate is 'm/2' and with exit velocity V2. As water is traveling over the curved plate there is no change of pressure on the entry and exit point of plate so P1 = P2 = P atm . At exit point 2, wat