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Hey friends,
My name is Aakash Ahlawat and I am a mechanical engineer. I will write my blogs on mechanical engineering subjects. If you want to clear your concept in mechanical subjects than stay connected to me. I will upload one blog weekly on different topics. All my audiences are requested to follow lectures according to serial number so that you have a better understanding. Hope you guys will enjoy this.
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Lecture - 11 (Transmission angle in four bar mechanism)

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The angle between coupler link and output link in four bar mechanism is known as transmission angle. It is represented as ' μ'.   In the given figure Let us consider angle between link AO and link OC (fixed link) is represented by ' θ'.   Let us consider length of link OC is 'a', length of link OA is 'b', length of AB is 'c' and length of BC is 'd'.  According to law of cosine we get -  Now  μ will be different for different values of  θ. μ will be maximum for  θ = 180 degrees  & minimum for  θ = 0 degrees.   Problem 1-  Calculate maximum and minimum value of transmission angle for the following mechanism. Length of link OC is 5cm, length of link AO is 1cm, length of link AB is 4cm and length of link BC is 3cm. Solution 1 -   To calculate minimum value of transmission angle observe the mechanism when  θ = 0 degrees   To calculate maximum value of transmission angle observe the mechanism when  θ = 180 degr
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Lecture - 8 ( problems on degrees of freedom)

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PROBLEM 1  - For the mechanism shown in figure, calculate it's degrees of freedom (F) SOLUTION 1  -  number of links (L) = 8 Number of binary joints (J) = 10 Number of higher pair (H) = 0 Number of those motions which are not the part of mechanism (N) = 0 KUTZBACH equation: F=3(L-1) - 2(J) - H - N F = 3(8-1) - 2(10) - 0 - 0 = 1 F = 1  PROBLEM 2 -  Calculate degrees of freedom for given mechanism SOLUTION 2 -   L = 4 ; J = 3 ; H = 1 ; N = 1 F = 3(L-1) - 2J - H - N = 3(4-1) -2(3) -1 -1 = 1 F = 1    PROBLEM 3 -  Calculate degrees of freedom for given mechanism.  SOLUTION 3 -   L = 5 ; H = 1 ; J = 5 ; N = 0 F = 3(5-1) -2(5) - 1 - 0 = 1  F = 1 PROBLEM 4 -  Calculate degrees of freedom for given mechanism SOLUTION 4 -    Here one link is spring. Spring is the link of flexible length. Spring can be replaced by 2 links connected with turning pair. L = 5 ; J = 5 ; H = 1 ; N = 0 F = 3(5-1) -2(5) - 1 = 1  F = 1
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Lecture - 15 (Mechanical advantage, mechanism efficiency, toggle mechanism)

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Mechanical advantage   It is defined as the ratio of the force produced by a machine to the force applied to it, used in assessing the performance of machine.  The combination of pulley system is shown in the below figure-  Here for lifting download F force is required but the effort given to the system is 8 times less, which is the good example of mechanical advantage. For the above system mechanical advantage is 8 Mechanical advantage = load / effort  Mechanical advantage for linear motion is -  Mechanical advantage for angular motion is -  Efficiency of system or mechanism Efficiency of the system is defined as the ratio of output power to the input power. PROBLEM - Find out mechanical advantage of the given mechanism having 100% efficiency. Solution -  In the sense of angular velocity It means that above mechanism is toogle mechanism.  Toggle mechanism   Those mechanism whose mechanical advantage is so high that it approaches
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